Question 1088343
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Please help me solve this question : {{{Sqrt(24-10x)}}} = 3-4x, 3-4x > 0.
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1.  Square both sides to get

    24 - 10x = {{{(3-4x)^2}}}

    24 - 10x = {{{9 - 24x + 16x^2}}}

    {{{16x^2 - 14x - 15}}} = 0

    (8x + 5)*(2x - 3) = 0

    The roots are x = {{{-5/8}}} and x = {{{3/2}}}.

    With  x = {{{3/2}}}  the expression  (24-10x)  under the square root is negative and therefore does not work.

    The only working solution is  x = {{{-5/8}}}.


    See the plot below.

    
{{{graph( 330, 330, -5.5, 5.5, -5.5, 10.5,
          sqrt(24-10x), 3-4x
)}}}


Plot y1 = {{{sqrt(24-10x)}}} (red) and y2 = 3-4x (green)
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