Question 1088327
27^1/3x=(1/9)^2x-1
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If you mean
{{{27^(x/3) = (1/9)^(2x-1)}}}
{{{3^x = (3^-2)^(2x-1)}}}
{{{3^x = 3^(-4x+2)}}}
x = -4x + 2
5x = 2
x = 2/5