Question 1088258
This is a binomial probability problem involving 8 trials, in which the probability of a "success" is 3/5.
In general, the probability of x successes out of n tries is:
P(x)=n!/(x!(n−x)!)p^x(1−p)^(n−x)
The mean of a binomial distribution is just n*p and the standard deviation is sqrt(n*p(1-p)
a. P(5) = 8!/(5!*3!)*0.6^5*0.4^3 = 0.2787
I will leave it as an exercise to compute the other values...