Question 1088305
if x is not equal to 1,2,3

we can solve this equation:

(x-3) + (x-1) = 2(x-1)(x-2)(x-3)/3

6x - 12 = 2(x^3-6x^2+11x-6)

x^3-6x^2+8x = 0

x(x^2-6x+8) = 0
x(x-2)(x-4) = 0 using restriction.

answer is {0,4}.

if we put x=0 on the first equation: 1/2 + 1/6 = 2/3 (true)
if we put x=4 on the first equation: 1/6 + 1/2 = 2/3 (true).

@natolino_