Question 1088250
 A kayaker can travel 1.2 miles downstream in the same time it takes him to go 0.4 miles upstream.
 If the river curent flows at 2 mph, what is the kayaker's speed in still water?
:
let s = his speed in still water
then
(s+2) = his speed downstream
and
(s-2) = his speed upstream
:
Write a time equation: time = dist'speed
upstream time = downstream time
{{{1.2/(s+2) = .4/(s-2)}}}
cross multiply
1.2(s-2) = .4(s+2)
Distribute
1.2s - 2.4 = .4s + .8
1.2s - .4s = .8 + 2.4
.8s = 3.w
s = 3.2/.8
s = 4 mph in still water
:
:
Check this find the actual time each way, should be equal
effective speed are 6 mph downstream and 2 mph upsteam
1.2/6 = .2 hrs
.4/2 = .2 hrs


 If the kayaker starts to freeze, can he build a fire in his kayak? Why or why not? 
Dumb question