<PRE><B>Question 96486</B>
two cyclists leave the city at the same time, one going east and the other going west. The westbound cyclist bikes 5mph faster than the eastbound cyclist. after 6 hours they are 246 miles apart. How fast is each cyclist riding?
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West-bound DATA:
Rate = x+5 mph ; time = 6 hrs. ; distance = 6(x+5) = 6x+30 miles
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East-bound DATA:
Rate = x mph ; time = 6 hrs. ; distance = 6x miles
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EQUATION:
distance + distance = 246 miles
6x+30 + 6x = 246
12x = 216
x = 18 mph (rate of East-bound cyclist)
x+5 = 23 mph (rate of West-bound cyclist)
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Cheers,
Stan H.
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