Question 96447
let the number be x, then:


{{{ x-x^3>2 }}}
{{{ x-x^3-2>0 }}}
{{{ x^3-x+2>0 }}}


So first find where {{{ x^3-x+2=0 }}}. The solution to this is not straight forward and i don't have time to write it all down here, sorry. You can re-submit or ask your teacher, sorry.


cheers
Jon