Question 1087983
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{{{cos(theta)}}} = x

{{{sin(theta)}}} = y.


Therefore, the rectangular form is

{{{sqrt(x^2 + y^2)}}} = {{{6/(3x + 4y)}}},   


or, if you square both sides


{{{x^2 + y^2}}} = {{{36/(3x+4y)^2}}}.
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