<PRE><B>Question 1087952</B>
2x^2 + 8x - 25 = 0
this will not factor, no integer solutions;  you have to use the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
In this equation, a=2; b=8; c=-25
{{{x = (-8 +- sqrt( 8^2-4*2*-25 ))/(2*2) }}}
:
{{{x = (-8 +- sqrt( 64 + 200 ))/4 }}}
:
 {{{x = (-8 +- sqrt( 264 ))/4 }}} 
:
 {{{x = (-8 +- 16.248)/4 }}} 
Two solutions
{{{x = (-8 + 16.248)/4 }}}
{{{x = 8.248/4 }}}
x = 2.062 
and
{{{x = (-8 - 16.248)/4 }}}
{{{x = (-24.248)/4 }}}
x =  -6.062     </PRE>