Question 1087933
n, the first of the three consecutive integers


{{{n+(n+1)+(n+2)=(1/3)(n+1)^2}}}

-



{{{3n+3=(1/3)(n^2+2n+1)}}}

{{{9n+9=n^2+2n+1}}}

{{{n^2-7n-8=0}}}

{{{(n+1)(n-8)=0}}}


the numbers
{{{system(n=8,n+1=9,n+2=10)}}}


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The numbers,  -1, 0, 1  also work.
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