Question 1087902
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There are two ways to go about this.  First, note that this is very close to a 30-60-90 right triangle (29 degrees is close to 30, and 61 degrees is close to 60) where the sides are in proportion:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2\sqrt{3}}{3}:1:\frac{\sqrt{3}}{3}]


Hence, the measures of the sides will be *[tex \Large \frac{16\sqrt{3}}{3}] for the hypotenuse, *[tex \Large 8] for side *[tex \Large b], and half of the hypotenuse or *[tex \Large \frac{8\sqrt{3}}{3}] for side *[tex \Large a].  Note that you will have to use the closest of the given answers because this answer will be slightly larger than the nearest tenth measure of side *[tex \Large a]


Or you could use the Law of Sines


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \frac{a}{sin(A)}\ =\ \frac{b}{sin(B)}]


Which is to say


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ a\ =\ \frac{8\sin(A)}{sin(B)}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  


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