Question 1087913
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The standard form of an equation of a circle is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


Where *[tex \Large (h,\,k)] are the coordinates of the center and *[tex \Large r] is the radius.  Note that you have to retain the minus sign that is given in the formula when you substitute a negative number for either h or k.  Hence, you end up with x plus something and/or y plus something if either h or k is negative.  Don't forget to square r.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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