Question 1087905
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This is a binomial distribution.  You want the probability of exactly 4 successes in 7 trials where the probability of success on any given trial is 30%.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(k,n,p)\ =\ {{n}\choose{k}} \left(p\right)^k\left(1\ -\ p\right)^{n-k}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(4,7,0.3)\ =\ \frac{7!}{4!(7\ -\ 4)!}\ \cdot\ \left(0.3\right)^4\ \cdot\ \left(1\ -\ 0.3\right)^{7-4}]


Just do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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