Question 1087861
PA, PB, PC splits triangle ABC into three triangles
:
let s be the length of a side of equilateral triangle ABC
:
5s/2 + 6s/2 + 7s/2 = s^2 * square root(3) / 4 (area of equilateral triangle)
:
divide both sides of = by s
:
5/2 + 6/2 +7/2 = (s * square root(3)) / 4
:
multiply both sides of = by 4
:
10 + 12 + 14 = s * square root(3)
:
s = 36 / square root(3)
:
multiply the numerator and denominator by square root(3)
:
s = 36 * square root(3) / 3 = 12 * square root(3)
:
s^2 = (12 * square root(3))^2 = 144 * 3 = 432
********************************************************
area of ABC = (432 * square root(3) / 4)
:
area of ABC = 108 * square root(3)
********************************************************
: