Question 1087735
this doesn't factor easily, so you need to use the quadratic formula.


that formula is:


<pre>


               -b plus or minus square root of (b^2 - 4ac)
     x =     -----------------------------------------------
                               2a
</pre>


the equation needs to be put in standard form of ax^2 + bx + c = 0


it's already in standard form.


this means that a = 1, b = -2, c = 2


plug those values into the quadratic formula and you get:


<pre>


               2 plus or minus square root of (4 - 4*1*2))
     x =     -----------------------------------------------
                               2*1
</pre>


you get:


<pre>


               2 plus or minus square root of (-4)
     x =     -----------------------------------------------
                               2
</pre>


square root of (-4) is equal to square root of (4 * (-1)) which is equal to 2 * square root of (-1).


square root of (-1) is equal to the letter i.


therefore square root of (-4) is equal to 2*i.


the value of the equation is equal to 0 when:


x = (2 + 2*i)/2 or x = (2 - 2*i)/2


simplify this to get:


x = 1 + i or x = 1 - i


use of a quadratic equation solver online confirms the solution is correct, as shown below:


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