Question 1087706
if you have {{{2}}} times {{{p^-1}}} and {{{3}}} times {{{q^-2}}}, we have

{{{2p^-1+3q^-2}}}

{{{2(1/p^1)+3(1/q^2)}}}

{{{2/p+3/q^2}}}

{{{2q^2/(pq^2)+3p/(pq)^2}}}

{{{(2q^2+3p)/(pq)^2}}}


but if you have {{{(2p)^-1}}} and {{{(3q)^-2}}}, we have

{{{(2p)^-1+(3q)^-2}}}

{{{1/(2p)^1+1/(3q)^2}}}

{{{(3q)^2/(2p(3q)^2)+(2p)/((2p)(3q)^2)}}}

{{{(9q^2+2p)/(2p*9q^2)}}}

{{{(9q^2+2p)/(18pq^2)}}}