Question 1087702

Assumes a {{{95}}}% level of confidence.

so, you can compute the margin of error {{{(MOE)}}} using this formula:

{{{MOE=t/sqrt(n)}}} where {{{t}}} is a desired {{{confidence}}} {{{level}}} and {{{n}}} is a random sample of a population

if {{{n=500}}} and {{{t=95}}}% 

{{{MOE=95/sqrt(500)}}}

{{{MOE}}}= ±{{{4.2485291}}}% ...round it

{{{MOE}}}=±{{{4}}}% 



so, your answer is: 

b. ±{{{4}}}%