Question 1087634
An object is launched into the air from a ledge 6 feet off the ground at initial vertical velocity of 96 feet per second. Its height H, in feet, at t second is given by the equation H = 16t2+96t+16. Find all the times t that the object is at a height of 160 feet off the ground.
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H = 16t2+96t+16
H = 16t2+96t+16 = 96
16t2+96t+16 = 96
16t2+96t-80 = 0
t^2 + 6t - 80 = 0
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*[invoke solve_quadratic_equation 1,6,-80]
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t = ~6.433 seconds (based on your info)
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You might notice that the object's height increases with time.  It never "comes down" or impacts.
That sorta makes sense if it'a rocket with thrust, but I doubt that's what the problem stated.