Question 1087661
Use algebra to determine 3 consecutive integers that add 
up to the largest integer less than 43.
<pre>Let smallest integer be S
Then others are: S + 1, and S + 2
The smallest INTEGER that's < 43 is 42
We then get: S + S + 1 + S + 2 = 42
3S + 3 = 42
3S = 39
{{{highlight_green(matrix(1,8, S, or, smallest, INTEGER, "=", 39/3, or, 13))}}}
{{{highlight_green(matrix(1,10, Other, INTEGERS, "are:", "13 + 1,", or, "14,", and, "13 + 2,", or, 15))}}}