Question 1087661
<pre>
Let x = the smallest of the three consecutive integers.
Then x+1 = the middle-sized of the three consecutive integers.
Then x+2 = the largest of the three consecutive integers.

{{{x+(x+1)+(x+2)}}}{{{""<""}}}{{{43}}}
{{{x+x+1+x+2}}}{{{""<""}}}{{{43}}}
{{{3x+3}}}{{{""<""}}}{{{43}}}
{{{3x}}}{{{""<""}}}{{{40}}}

{{{x}}}{{{""<""}}}{{{40/3}}}

{{{x}}}{{{""<""}}}{{{13&1/3}}}

The largest integer less than {{{13&1/3}}} is 13.

So the three consecutive integers are 13,14,and 15. They add to 42.

Edwin</pre>