Question 1087657
In this case we can use Hypergeometric Distribution with N=52 (total number of cards), n= 3 (number of dealt cards), d = 4 + 4 + 4 = 12 (total working cards)

P(X=x) = (dCx)* ((N-d)C(n-x))/(NCn).

P(X>=1) = 1 - P(x=0) (using the complement rule).

Using the general term with x=0, P(x=0) = (12C0)(40C3)/(52C3) = 38/85.

So the answer is 1 - 38/85 = 47/85 =0,553

@natolino_