Question 1087530
{{{(x+1)^(2)=-4(y-3)}}}


vertex (-1,3)
focus (-1,2)
directrix y=4


{{{(x+1)^2=-4(2-3)}}}
{{{(x+1)^2=4}}}
{{{x+1=0+- 2}}}
{{{system(x=-1-2,or,x=-1+2)}}}
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Endpoints of focal width (-3,2) and (1,2)


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{{{y-3=(-1/4)(x+1)^2}}}
{{{y=3-(1/4)(x+1)^2}}}
{{{y=-(1/4)(x+1)^2+3}}}

{{{graph(300,300,-6,4,-5,5,-(1/4)(x+1)^2+3)}}}