Question 1087474
the slopes of perpendicular lines have a negative reciprocal product, or -1.
the slope of the other line is 3/4
y-y1=m(x-x1), m slope, (x1,y1) point
(y-6)=(3/4)(x+5)
y=(3/4)x+(39/4)
{{{graph(300,300,-10,10,-10,10,(-4x/3)-4,(3x/4)+(39/4))}}}