Question 1087496

{{{2(8-4(3-x))-2=8(2(4x-3)+7)-50}}} ...I will highlight inside parentheses 

{{{2(8-highlight(4(3-x)))-2=8(highlight(2(4x-3))+7)-50}}}...first multiply what is  highlighted to eliminate parentheses 

{{{2(8-(12-4x))-2=8((8x-6)+7)-50}}}...eliminate parentheses inside parentheses


{{{highlight(2(8-12+4x))-2=highlight(8(8x-6+7))-50}}}.......multiply what is  highlighted 

{{{16-24+8x-2=64x-48+56-50}}}

{{{8x-10=64x-42}}}

{{{42-10=64x-8x}}}

{{{32=56x}}}

{{{x=32/56}}}

{{{x=4/7}}}