Question 1087447
Are you asking about the probability of choosing 2 red balls and 2 white balls?
In that particular order,
{{{P= (3/7)(2/6)(4/5)(3/4) =3/35}}}
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In any order, there are 6 possible outcomes,
{RRWW}
{RWRW}
{RWWR}
{WWRR}
{WRWR}
{WRRW}
So,
{{{P=6(3/35)=18/35}}}