Question 1087389
1.
{{{2x^2-8x>0}}}
{{{2x(x-4)>0}}}

solutions:
{{{2x>0}}} =>{{{x>0}}} or
{{{(x-4)>0}}} =>{{{x>4}}}

interval:

({{{-infinity}}},{{{0}}}) U ({{{4}}},{{{infinity}}})

2.
{{{2x^2-8x<0}}}
{{{2x(x-4)<0}}}

solution:
x<0 or x<4.....g is negative between {{{0}}} and {{{4}}};so,interval is

{{{0<x<4 }}}

interval notation:

({{{0}}},{{{4}}})


{{{ graph( 600, 600, -10, 10, -10, 10, 2x^2-8x) }}}