Question 1087387
{{{f(x)=a(x-9/2)^2+0}}}
So when {{{x=0}}},
{{{1/6=a(0-9/2)^2+0}}}
{{{a(81/4)=1/6}}}
{{{a= (1/6)(4/81) }}}
{{{a=2/243}}}
{{{f(x)=(2/243)(x-9/2)^2}}}
or
{{{f(x)=(2/243)(x^2-9x+81/4)}}}
{{{f(x)=(2/243)x^2-(2/27)x+1/6}}}