Question 1087358
If the gravity on Mars is equal to -12 ft./sē, then the formula for a projectile, launched from a platform 36 ft. high, with a velocity of 30 ft./sec., would be:
h(t)=-12/2 tē+30t+36
After 3 seconds, you have:
h(3)=-6(9)+90+36=72 ft.
The ball will return to Mars at:
0=-6tē+30t+36
6tē-30t-36=0
tē-5t-6=0
(t-6)(t+1)=0
t=6 seconds before the ball hits the Martian surface.
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