Question 1087351

{{{((32a^4b^(-2))/(2a^3b^3))((3a^2b^7)/(-2a))}}}...simplify


{{{((cross(32)16a^cross(4)^1b^(-2))/(cross(2)cross(a^3)b^3))((3a^cross(2)^1b^7)/(-2cross(a)))}}}


{{{((16ab^(-2))/b^3)((3ab^7)/(-2))}}}....recall that {{{b^(-2)=1/b^2}}}


{{{(16a/(b^2*b^3))((3ab^7)/(-2))}}}


{{{(16a/b^5)((3ab^7)/(-2))}}}


{{{(cross(16)8a/cross(b^5)1)((3ab^cross(7)^2)/(-cross(2)1))}}}


{{{(8a/1)((3ab^2)/(-1))}}}


{{{(8a)(-3ab^2)}}}....multiply 


{{{-24a^2b^2}}}