Question 1087296
<font color="black" face="times" size="3">Assuming there isn't any wind resistance, the answer is about <font color=red>13.043197 seconds</font>


See below on how I got that value.


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{{{s = 16t^2}}}


{{{2722 = 16t^2}}} Replace 's' with the given height. The goal is to solve for t


{{{2722/16 = (16t^2)/16}}} Divide both sides by 16


{{{170.125 = t^2}}}


{{{t^2 = 170.125}}}


{{{sqrt(t^2) = sqrt(170.125)}}} Apply the square root to both sides


{{{t = sqrt(170.125)}}} Keep in mind that negative t values make no sense, so {{{t >= 0}}}


{{{t = 13.0431974607456}}} Use a calculator to compute the square root


{{{t = 13.043197}}} I'm deciding to round to 6 decimal places. You can round to whatever you want depending on your teacher's preference.


Side Note: this is assuming that there is no wind or air resistance. The object would have to be in a vacuum for this solution to make sense. Of course, such a scenario is very unlikely. The teacher is opting to ignore air resistance because that topic involves much more complicated math. </font>