Question 1087275
{{{4=2^2}}}
{{{8=2^3}}}
So,
{{{4^(3x-1)=8^(x+1)}}}
{{{(2^2)^(3x-1)=(2^3)^(x+1)}}}
{{{2^(2*(3x-1))=2^(3*(x+1))}}}
Then,
{{{2(3x-1)=3(x+1)}}}
{{{6x-2=3x+3}}}
{{{3x=5}}}
{{{x=5/3}}}