Question 1087189

{{{5/(n-3) - 2/(n+2)}}}

 = {{{5(n+2)/((n-3)(n+2)) - 2(n-3)/((n-3)(n+2))}}}

 = {{{(5(n+2) - 2(n-3))/((n-3)(n+2))}}}

 = {{{(5n+10 - 2n+6)/((n-3)(n+2))}}}

 = {{{(3n+16)/((n-3)(n+2))}}}