Question 1087142


the standard form of 

{{{4x^2+4y^2-16x+40y+67=0 }}}..........complete squares

{{{(4x^2-16x)+(4y^2+40y)+67=0 }}}

{{{4(x^2-4x+b^2)-4b^2+4(y^2+10y+b^2)-4b^2+67=0 }}}

{{{4(x^2-4x+2^2)-4*2^2+4(y^2+10y+5^2)-4*5^2+67=0 }}}

{{{4(x-2)^2-16+4(y+5)^2-100+67=0 }}}

{{{4(x-2)^2+4(y+5)^2-49=0 }}}

{{{4(x-2)^2+4(y+5)^2=49 }}}

{{{(x-2)^2+(y+5)^2=49/4}}}