Question 1087158

The conics form of the parabola equation (the one you'll find in advanced or older texts) is:

    regular: {{{4p(y -k) = (x - h)^2}}}
    sideways: {{{4p(x-h) = (y -k)^2}}}.......... since focus is at ({{{4}}},{{{0}}}), you need this formula

{{{4p(x-h) = (y -k)^2}}}............since vertex is the origin we have
{{{4p(x-0) = (y -0)^2}}}
{{{4px = y ^2}}}............since  focus is at ({{{4}}},{{{0}}})and {{{p}}} is the distance between the vertex and the focus, {{{p=4}}}

{{{4*4x = y ^2}}}

{{{y ^2=16x }}}


{{{drawing(600, 600, -10, 10, -10, 10,
circle(4,0,.12), locate(4,0.6,F(4,0)),
 graph(600, 600, -10, 10, -10, 10,sqrt(16x), -sqrt(16x))) }}}