Question 1087111


 {{{log(x) = -2.238}}} .........in base {{{10}}} we have

{{{(log(x))/(log(10)) = -2.238}}}

{{{log(x)= -2.238(log(10)) }}}

{{{log(x)= log(10^-2.238)}}}

{{{x= 10^(-2.238)}}}

{{{x= 1/(10^(2.238))}}}

{{{x= 0.00578096}}}

{{{x= 0.006}}}