Question 1087096
63 animals, an 5:4 cats to dogs; because 63/9 (5+4)=7, the shelter has 35 cats and 28 dogs.
40% of the 35 cats are kittens, which is 14.  3/7 of the dogs are puppies, so that is 12.
If 6 animals are chosen at random, probability NONE is a kitten is 
(49/63)*....(44/58)=0.2058; take the complement and get your result of 79.42%
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choosing 8 adult animals, which includes 21 cats and 16 dogs or 37 altogether
Total number of choices is 37C8
The numerator will be of the form 21C4*16C4=10892700
other possibilities are 21C5*16C3=11395540; divide this by 37C8=0.2952
and 21C3*16C5=5809440
check 21C6*16C2=6511680
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10 babies are chosen from 14 kittens and 12 puppies.  It will be skewed, since there are unequal numbers of both.
Look at the probability of 5 of each, 6 and 4, and 4 and 6
14C5 * 12C5=1585584
14C6*12C4=1486485
14C4*12C6=924924
This is not symmetrical, as expected.