Question 1087052
log_5(x-8)=1-log_5(x-4)
log_5(x-8)+log_5(x-4)=1
log_5(x-8)+log_5(x-4)=log_5(x-8)(x-4)=log_5(x²-12x+32)=1
x²-12x+32=5
x²-12x+27=0
(x-9)(x-3)=0
Since you can't take the logarithm of a negative number, your one answer is x=9
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