Question 1086577

solve the simultaneous equation
(A) Logx=y=1/2log(2x-1) all log is in base 3

(B) logx=y=log(2x-1),the first log is in base 3 while the second log is in base 9
<pre>AMBIGUOUS! 
If you need a correct answer (I would imagine you would), then fix and re-post!