Question 1082947
The volume of a cube is,
{{{V=s^3}}}
The maximum volume allowed is,
{{{V[max]=10.015}}}
So,
{{{s^3=10.015}}}
{{{s=2.155511}}}{{{m}}}
If it was perfect,
{{{s^3=10}}}
{{{s[p]=2.154435}}}
So then,
{{{E=abs(s[p]-s)}}}
{{{E=abs(2.154435-2.155511)}}}
{{{E=0.001077}}}
So the edge must be,
{{{s[I]=2.154 +- 0.001}}}{{{m}}}