Question 1086937
Find the sum of this series: 3 + 6 + 12 + 24 + 48 + …; 10th term.
a. 6742
b. 2455
c. 3069
<pre>Sum of a GP, or {{{matrix(1,3, S[n], "=", a[1] * ((1 - r^n)/(1 - r)))}}}, with:
{{{S[n]}}} = Sum of "n" terms (Unknown, in this case)
{{{a[1]}}} = 1st term (3, in this case)
{{{r}}}  = Common ratio (2, in this case)
{{{n}}}  = Number of terms (10, in this case)

{{{matrix(1,3, S[n], "=", a[1] * ((1 - r^n)/(1 - r)))}}} then becomes: {{{matrix(1,3, S[10], "=", 3 * ((1 - 2^10)/(1 - 2)))}}}, and then:
{{{highlight_green(matrix(1,9, S[10], "=", 3 * ((1 - "1,024")/(1 - 2)), "=", 3 * ((- "1,023")/(- 1)), "=", 3("1,023"), "=", highlight(matrix(1,3, "3,069", "(CHOICE", "c.)")))))}}}