Question 1086825
{{{a[1]=0.3}}}
{{{d=a[2]-a[1]=0.7-0.3=0.4}}}
{{{a[n]=a[1]+(n-1)*d}}}
Substituting,
{{{a[n]=0.3+(n-1)(0.4)}}}
{{{a[n]=0.3+0.4n-0.4}}}
{{{highlight(a[n]=0.4n-0.1)}}}