Question 1086777
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First multiply by 4 then complete the square.
{{{4(x^2-5x+3)=4x^2-20x+12=0}}}
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More sensible to complete the square, form your expression inside the grouping, and after that to multiply by the 4.


{{{4(x^2-5x+3+(5/2)^2-(5/2)^2)}}}


{{{4(x^2-5x+(5/2)^2+3-(5/2)^2)}}}


{{{4((x-5/2)^2+3-25/4)}}}


{{{4(x-5/2)^2-13=0}}}
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