Question 1086768
Let n be the length of the short side. Then the longer leg is n+4, and the hypotenuse is n+8. So:
n²+(n+4)²=(n+8)²
2n²+8n+16=n²+16n+64
n²-8n-48=0
(n-12)(n+4)=0
n=12,-4
Your legs are 12, 16, and 20
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