Question 1086737
<pre>
48 is a multiple of 6, so it's the first term

295/6 = 49.16667, so the largest multiple of 6 less than
295 is 6 times the whole part of 49.16667 which is 49.
That's 6*49 or  294.

{{{a[n]=a[1]+(n-1)d}}}
{{{294=48+(n-1)6}}}
{{{294=48+(n-1)6}}}
{{{246=6(n-1)}}}
Divide both sides by 6
{{{41=n-1)}}}
{{{42=n}}}

{{{S[n]=expr(n/2)(a[1]+a[n])}}}
{{{S[42]=expr(42/2)(48+294)}}}
{{{S[42]=21(342)}}}
{{{S[42]=7182}}}

Edwin</pre>