Question 1086682
{{{2x-3y+3=0}}}
{{{-3y=-2x-3}}}
{{{y=(2/3)x+1}}}
Center on a general point   ( x, (2/3)x+1 ).


A(-3,1) point on circle
2, radius of circle


{{{(x-(-3))^2+((2x/3+1)-1)^2=2^2}}}, which would come from using Distance Formula.  Solve this to get a solution for x, and use it to find y, for your circle's center point.