Question 1086692
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x- intercepts are intersection points of the parabola f(x) with the x-axis, where 

   f(x) = 0,  or,  which is the same,  {{{(x+2)^2-16}}} = 0.


So, you need to solve the equation  {{{(x+2)^2-16}}} = 0.

It is equivalent to  {{{(x+2)^2}}} = 16.


Take the square root from both sides.  You will get

x + 2 = +/- 4.


So, there are two options and two solutions. They are


1)  x + 2 = 4   ====>  x = 4 - 2 = 2.


2)  x + 2 = -4  ====>  x = -4 - 2 = -6.


<U>Answer</U>.  There are two solutions: x= 2  and  x= -6.
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Solved.