Question 1086586
let one side of the rectangle be {{{a}}} and the other side {{{b}}}

if one side of the rectangle exceeds three times the other side by {{{2 }}} centimeters, we have

{{{a=3b+2}}}.....eq.1


 if the perimeter is {{{52}}} centimeters, we have:

{{{2a+2b=52}}}...both sides divide by {{{2}}}

{{{a+b=26}}}.......eq.2...substitute {{{a}}} from eq.1


{{{3b+2+b=26}}}......solve for {{{b}}}

{{{4b=26-2}}}

{{{4b=24}}}

{{{b=24/4}}}

{{{b=6}}}

find {{{a}}}


{{{a=3b+2}}}.....eq.1

{{{a=3*6+2}}}

{{{a=18+2}}}

{{{a=20}}}


so, the length of the sides are {{{20}}} and {{{6}}}