Question 96246
{{{3y^2 + 10y + 7}}}
comparing the above equation with standard quadratic equation {{{ay^2+by+c=0}}}
we get

a = 3
b = 10
c = 7

Discriminant:{{{ b^2-4ac = 10 2-4*3*7 = 16 }}}

Discriminant (16) is greater than zero. The equation has two solutions.

{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
or
{{{y = (-10 +- sqrt( 10^2-4*3*7 ))/(2*3) }}} 


{{{ y = (-10 +- 4) / (2*3) }}}

or


{{{ y1 = -6 / 6 = -1 }}}

{{{ y2 = -14 / 6 = -7/3 }}}

Equation factored:

{{{3(x+1)(x+7/3) }}}