Question 96205
Please help me solve this problem:
{{{y^(4/3) = -3y}}}
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Why don't you just do this, cube both sides
{{{(y^(4/3))^3}}} = {{{(-3y)^3}}}
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Gets rid of the denominator in the exponent
{{{y^4}}}= {{{-3^3*y^3}}}
:
{{{y^4}}}= {{{-27*y^3}}}
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Divide both sides by y^3
{{{(y^4)/(y^3)}}} = -27
 y = -27
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Check solution in calc: 
(-27)^(4/3) = 81
and
-3*-27 = 81
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