Question 1086422
.
In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
~~~~~~~~~~~~~~~~~~~~~~~~~~


I will not follow your solution and will develop my own solution instead.


<pre>
In the original mass of 126 kg of the mixture there are 7 (= 5 + 2) equal parts (masses).

Hence, the milk  contents is {{{5*(126/7)}}} = 5*18 = 90 kg,
       and water contents is {{{2*(126/7)}}} = 2*18 = 36 kg.


OK.


Next, the final mixture, having 90 kg of milk, must contain {{{(90/3)*2)}}} = 30*2 = 60 kg ow water to provide the ratio {{{milk/water}}} = {{{3/2}}}.


Hence,  60 - 36 = 24 kg of water must be added to the original mixture to satisfy the problem requirements.
</pre>

<U>Answer</U>.  24 kg of water must be added to the original mixture.



Solved.